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In rabbits, the self coloring is caused by a recessive gene, a. A breeder has a buck that she wants to use for breeding purposes if possible. The rabbit is Agouti, so the owner knows his genotype is either AA or Aa. If the rabbitss genotype is Aa, the owner does not wish to use him for breeding so that the self gene will not be passed on. This can be tested by breeding the buck to a self doe (aa). Draw the Punnett squares to illustrate these two possible crosses. In each case, what percentage/how many of the offspring would be expected to be Agouti? self? How could you tell the genotype of this male dog? Also, using Punnett square(s), show how two Agouti rabbits could produce a self offspring.
In rabbits, black (B) dominant over chocolate (b). A black rabbit is bred to a chocolate doe and they have three kits, two of whom are black and one of whom is chocolate. Draw the Punnett square that illustrates this breeding. What is the bucks genotype? What are the genotypes of the kits?
Lets say a chocolate doe has two Agouti alleles which can be represented by AA. Lets say a buck has an agouit and a self allele, so we say they are Aa. Draw the Punnett square for the previous problem also keeping track of the A Lotus of the various individuals.
In rabbits, Agouti hair (A) is dominant over self (a), Black (B) is dominant over chocolate (b), and non-dilute (D) is dominant over dilute (d). Assuming these genes are on separate chromosomes, draw the Punnett square for a cross between a homozygous Black Agouti Nondilute and a Dilute Chocolate Agouti. What would the phenotype(s) of the offspring be? If two of the F1 offspring were crossed, draw the Punnett square for this cross. Hint: first make a list of the possible gametes, making sure each has exactly one copy of each of the genes (one allele for each gene). What would the genotype and phenotype ratios be for the F2 generation?